I recently had a Coke Zero and noticed that they had a competition on (https://www.coke.co.nz/cash) :
Check under specially marked labels on 'Coca-Cola', 'Coca-Cola Zero' and 'Diet Coca-Cola' 600mL bottles to see if you are a winner of $20, $50 or $100.There is $200k in prizes to be won, so I asked myself: how many of each price is there?
x = number of $20 prizes
y = number of $50 prizes
z = number of $100 prizes
so 20x + 50y + 100z = 200,000
update: I forgot to mention that there are 4,600 prizes, so x + y + z = 4600
With some headscratching I rejigged the problem to:
x = 5n
y = 8(650-n)
z = 3(n-200)
200 <= n &<= 650 if we want positive results
I then explored that range with excel to see what my best guess is for the distribution of cash:
$20 | $50 | $100 | n | |
1000 | 3600 | 0 | 200 | |
2000 | 2000 | 600 | 400 | Min where x <= y <= z |
2005 | 1992 | 603 | 401 | Min where x < y < z |
2375 | 1400 | 825 | 475 | Nearly equal ratios (~1.7/1) |
2500 | 1200 | 900 | 500 | Nice round numbers |
2635 | 984 | 981 | 527 | Max where x > y > z |
So there we have it, my best guess is the round numbers (though even ratios is nice):
2500 x $20 + 1200 x $50 + 900 x $100 = $200k
update: I found on https://www.coke.co.nz/cash/conditions-of-entry the answer (n = 300), which wasn't on the label:
The instant win prizes available to be won (the Cash Prizes) are:
- (a) 1,500 x cash prizes valued at $20 each;
- (b) 2,800 x cash prizes valued at $50 each; and
- (c) 300 x cash prizes valued at $100 each.
Surprising that there is more $50s than $20s.
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